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guajiro [1.7K]
3 years ago
10

Plz help! i dont understand how to do this1

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0
A  and   c because you will have to 

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The equation would be y = 7.50x - 8.
The graph would be an increasing straight line.
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a national monument had 160,747 visitors during the first week of september . a total of 759,656 people visited the monument in
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598,909 is the answer because when I put that for a test I got it right
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Solve for x in the following equation 4×/3=4 x=12,x=28,x=3,x=16​
KonstantinChe [14]

Answer:

x= 3

Step-by-step explanation:

mark me brainliest :)

8 0
4 years ago
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Find the a. MEAN and b. STANDARD DEVIATION for the data set. Round to two decimal places.
Dafna11 [192]

Answer:

Explained below.

Step-by-step explanation:

(10)

The data set is:

S = {124, 94, 129, 109, 114}

The mean and standard deviation are:

\bar x=\frac{1}{n}\sum x=\frac{1}{5}\times [124+94+...+114]=114\\\\s=\sqrt{\frac{1}{n-1}\sum ( x-\bar x)^{2}}

  =\sqrt{\frac{1}{5-1}\times [(124-114)^{2}+(94-114)^{2}+...+(114-114)^{2}]}\\=\sqrt{\frac{750}{4}}\\=13.6931\\\approx 13.69

The correct option is B.

(11)

According to the Empirical 95% of the data for a Normal distribution are within 2 standard deviations of the mean.

So, the adult male's height is in the same range as about 95% of the other adult males whose heights were measured.

The correct option is B.

(12)

Let the score be <em>X</em>.

Given:

μ = 100

σ = 26

X=\mu-2\sigma

    =100-(2\times 26)\\=100-52\\=48

The correct option is B.

(13)

Let <em>X</em> be the prices of a certain model of new homes.

Given: X\sim  N(150000, 2300^{2})

Compute the percentage of buyers who paid between $147,700 and $152,300 as follows:

P(147700

                                         =P(-1                                        

According to the 68-95-99.7, 68% of the data for a Normal distribution are within 1 standard deviations of the mean.

The correct option is D.

(14)

Compute the percentage of buyers who paid more than $154,800 as follows:

P(X>154800)=P(\frac{X-\mu}{\sigma}>\frac{154800-150000}{2400})

                                         =P(Z>2)\\=0.975\\

According to the 68-95-99.7, 95% of the data for a Normal distribution are within 2 standard deviations of the mean. Then the percentage of data above 2 standard deviations of the mean will be 97.5% and below 2 standard deviations of the mean will be 2.5%.

The correct option is D.

(15)

The <em>z</em>-score is given as follows:

z=\frac{x-\mu}{\sigma}

5 0
3 years ago
Simplify -19 – 1 + (–24)
IrinaK [193]
First subtract -19 - 1 = -20

Next, + (-24) is the same as just simply subtracting 24

-20 - 24

Subtract that and you get -44
3 0
3 years ago
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