First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
Answer:
[7-2x+5y-(x-y) -[5x+3y-7]
= 7-2x+5y-x+y-5x-3y+7
=7+7-2x-x-5x+5y+y-3y
=14-8x+3y
=-8x+3y+14
Step-by-step explanation:
Answer:
im kind of rusty on this math but i think the equation would be y=-5x+b i forgot how to find b tho :( im sorry
Answer:
m = -12 / 6 = -2 / 1 = -2
So its -2
