Brainliest???
If the resulting daughter cells are too damaged to undertake further cell divisions, the mutation would not be propagated and no harm comes to the organism
Answer:
The correct answer is - neurulation
Explanation:
The neural groove is a groove of the neural plate which is a thick plate that is enclosed by the neural folds of an embryo. The neural grove forms the neural tube which expands and develops into the spinal cord and brain.
The development of the neural grove is taken place during the process known as neurulation which is characterized by all characteristic development related to the neural groove and ventricular system.
According to the research, the correct option is exocytosis. Insulin is made by pancreatic cells, packaged in small vesicles, and then released into the bloodstream. This describes <u>exocytosis</u> cell transport.
What is exocytosis?
It is the expulsion, by cells, of particles that, due to their size, cannot pass through the cell membrane.
In this sense, it is the process by which different types of molecules contained in a cytoplasmic vesicle of a cell are secreted. Insulin is released to the outside by exocytosis, intervening in the process of glucose entry into cells.
Therefore, we can conclude that according to the research, the correct option is exocytosis. Insulin is made by pancreatic cells, packaged in small vesicles, and then released into the bloodstream. This describes <u>exocytosis</u> cell transport.
Learn more about exocytosis here: brainly.com/question/1193597
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