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3 years ago

I need help with all of number 2 pls

Mathematics

1 answer:

Liula [17]3 years ago

7 0

Well just try to add the stuff from the top and add it

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6k < 100 Check all that are true. k = 5 k = 15 k = 10 k = 20

Elden [556K]

Answer:

True: 5, 15, and 10

Step-by-step explanation:

6*5=30 Correct, 30 is less than 100

6*15=90 Correct, 90 is less than 100

6*10=60 Correct, 60 is less than 100

6*20=120 Wrong, 120 is greater than 100

7 0

3 years ago

Read 2 more answers

Which is greater 30% 0.03

jolli1 [7]

Answer:

30% is greater

Step-by-step explanation:

30% = 0.3

0.3 > 0.03

3 0

3 years ago

Given f(g(x)) = 15x+1 and f(x) = 5x+1. What is g(x)? Please answer quickly!!

natka813 [3]

Suppose you are given the two functions f (x) = 2x + 3 and g(x) = –x2 + 5. Composition means that you can plug g(x) into f (x). This is written as "( f o g)(x)", which is pronounced as "f-compose-g of x". And "( f o g)(x)" means " f (g(x))".

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4 years ago

Describe two ways to find the maximum area for rectangles with a fixed perimeter

____ [38]

Either multiply length by width, or measure all sides and add together
LxW=Area
S1+S2+S3+S4=Area

8 0

3 years ago

2. A square-based tent has the cross-sectional

ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

Explanation:

An image is attached for reference.

(a)

In ΔAOB,

$sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m$

In ΔBGD,

$sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m$

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

= 1 m + 1.732 m

= 2.732 m

(b)

DF = ?

In ΔAOB,

$tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\$

According to the figure, OB = GE = 1.733 m

In ΔBGD,

$tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m$

According to the figure, DE = DG + GE

DE = 1 m + 1.733 m

DE = 2.733 m

Length of the base, DF = 2 X DE

DF = 2 X 2.733 m

DF = 5.466 m

8 0

3 years ago