The two sets of parametric equations for the rectangular equation are;
- If x=t+6 then y= t²-7t-42.
- If x=7t then y= 49t² - 133t +36.
<h3>What are the parametric equations from the rectangular equation?</h3>
It follows from the task content that the parametric equations can be determined as follows;
By substituting the x= t+6 into the rectangular equation; we have;
y = (t+6-6)²-7(t+6)
y = t²-7t-42.
By substituting the x= 7t into the rectangular equation; we have;
y = (7t-6)² -7(7t)
y = 49t² - 84t +36 - 49t
y = 49t² - 133t +36.
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You have to use this equation the a=5, h=4 and b=9 and you should get the answer of 28
Answer:
Step-by-step explanation:
X +2=12y
X-12y=-2
-12xy=-2
Xy=-2/-12
Xy=6
1. We need to get rid of all the denominator in this equation.
- This can be done by multiplying left and right sides by the LCD.
- In the problem: 12/x = 8, the LCD is X.
12/x = 8 is now 12 = x * 8
1a. 8 * x = 8x
Now, your answer is 3/2, but It's improper. Let's convert it into a mixed number.
Subtract 3 by 2.
3 - 2 = 1
3/2 = 1 1/2
Therefore, your answer is 1 1/2. Also, the answer is 1.5.
Answer:
derivative of the vector function given = ( -16-22t, 14-36t, -2-16t )
Step-by-step explanation:
given data:
vector function : r(t) = ta*(b+tc)
a = ( 2,-3.4) . b = (-4,5,-1). c = ( -2,-1,5)
to find the derivative of the vector function we will differentiate with respect to x attached below is the detailed solution
