$2x^2-12xy-32y^2=2(x-8y)(x+By)\qquad|\text{use distributive property}\\\\2x^2-12xy-32y^2=(2x-16y)(x+By)\\\\2x^2-12xy-32y^2=(2x)(x)+(2x)(By)+(-16y)(x)+(-16y)(By)\\\\2x^2-12xy-32y^2=2x^2+2Bxy-16xy-16By^2\\\\2x^2-12xy-32y^2=2x^2+(2B-16)xy+(-16By)$

$\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT$

<h3>Answer: B = 2</h3>

8 0

3 years ago

Please help ASAP?!!!!

ra1l [238]

It is C prob i need point lol i’m sorry

4 0

2 years ago

If 1+4=5 and 2+5=12 and 3+6=18 what does 8+11=

stepladder [879]

1+4=5 & 2+5=12 THE REASON FOR 2+5=12 IS <span>5+2+5=12
</span>So the same is for the next

6 0

2 years ago

The product of two mixed numbers that are each between 4 and 5 is between 16 and 25

nalin [4]

4.5x5=22.5

not sure if this is right, but hope it helps

6 0

3 years ago