Answer:
everyone got 6 pieces
Step-by-step explanation:
do you actually need a explanation?
Answer:
<h3>
The width (side perpedicular to the barn):
<u>x = 8 m</u></h3><h3> The lenght (side parallel to the barn):
<u>y = 16 m</u> </h3>
Step-by-step explanation:
x - the width of the barn
She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:
y = 32 - 2x
Area of the fencing: A = x•y
A(x) = x•(32 - 2x)
A(x) = -2x² + 32x ← quadratic function
The maximum value of quadratic function occurs at: 
a = -2, b = 32

32-2x = 32 - 2•8 = 16
Answer:

Step-by-step explanation:
arithmetic sequence formula: 
where
is the first term and
is the common difference
Given:
⇒ 
⇒ 
Given:

⇒ 
⇒ 
Rearrange the first equation to make
the subject:
a = 32 - 9d
Now substitute into the second equation and solve for 
(32 - 9d) + 11d = 106
⇒ 32 + 2d = 106
⇒ 2d = 106 - 32 = 74
⇒ d = 74 ÷ 2 = 37
Substitute found value of
into the first equation and solve for
:
a + (9 x 37) = 32
a + 333 = 32
a = 32 - 333 = -301
Therefore, the equation is: 
Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions
and
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction
shown in purple, then we can plot the second one
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.