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Westkost [7]
3 years ago
12

What transformation maps the preimage (red) onto the image (blue)?

Mathematics
2 answers:
Dominik [7]3 years ago
8 0

Answer:

Rotate counter clockwise about the center point 180 degrees

Step-by-step explanation:

You can use transformations to preserve shape and size but move a shape or change its position. Transformations include:

  • reflection - a flip across an axis
  • rotation - a turn around a point
  • translation - a slide a specific distance and direction

To map the red into the blue, you can rotate it counter clockwise about the center point which the red and blue shapes share 180 degrees. It will land exactly on the red.

Trava [24]3 years ago
3 0

Answer:

Rotation

Step-by-step explanation:

Hope this helps!

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What is the number 21.0384 rounded to the nearest hundredth?
Anton [14]

Answer:

21.04

Step-by-step explanation:

the 8 is closest to 10 so that would make the 3 a 4.

3 0
3 years ago
Bob is a bus driver, and his monthly salary is $1510. If the New York State income tax rate is 6.45%. How much did the money ded
viva [34]

Answer:

<h2>i. $97.4</h2><h2>ii. $1412.6</h2>

Step-by-step explanation:

step one:

given data

Bob's  monthly salary is $1510

tax= 6.45%

Required

The deduction and his take-home salary

Step two:

let us compute the deduction

=6.45/100*1510

=0.0645*1510

=$97.4

Let us compute his take home

=monthly salary- tax deduction

=$1510-$97.4

=$1412.6

6 0
3 years ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
3 years ago
Please Help I Need The Awnsers
Law Incorporation [45]

x= 113°

hope that helps^^

8 0
3 years ago
Karen is working on her math homework. She solves the equation
Gelneren [198K]
Disagree.
b/8 = 56; multiply both sides by 8 to solve for b, and you get b = 448
5 0
3 years ago
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