<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>
To solve this problem, we would write out two set of linear equations.
The data given on this problem are
- parent-teacher conference = $35.50
- school related assembly = $42
- The total number of engagements = 27
Let x represent the number of parent-teacher conference
let y represent the number of school related conference
<h3>Equations</h3><h3>

</h3>
From equation (i)

Put equation(iii) into equation (ii)

Put y = 5 into equation 1

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.
Learn more on linear equations here;
brainly.com/question/4074386
Answer:
the answer its 7^2 +7^3x5 its d hope helps you
Step-by-step explanation:
55% x n = 33
divide 33 by .55
n = 60
Answer:
$12.50
Step-by-step explanation:
Divide the total amount by the number of trophies
152 ÷16 = 9.5
than add 3 to your total
9.5 + 3= 12.5
since where dealing with money add a zero and a dollar sign.
$12.50
Exponents inside the parentheses are done first
eg. 5 + (25- 2) = ?
You would do the numbers inside first
25-2=23 to get 5 + 23 = 28
:)