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gogolik [260]
3 years ago
12

Jose is training for a marathon.If he ran 160.2 miles in january, 163.2 miles in February, 157.8 miles in march, and 159 miles i

n April, how can we use clustering to estimate how far he ran in those 6 months?
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer: I think it's 960.

Step-by-step explanation:

Add up all of the numbers:

(160.2+163.2+157.8+159) = 640.2

Find the average by diving 640.2 by how many numbers there are:

640.2 ÷ 4 = 160.05

Round that average^^:

160.05 >>> 160

Multiply by how many numbers there will be:

In this case, your job is to estimate how far Jose ran in 6 months, not just those 4. So instead of multiplying the average (160) by 4, you'd multiply it by 6.

160 x 6= 960

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In a G.P., the third term exceeds the first term by 16.
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Answer:

Step-by-step explanation:

In a G.P, the nth term is given as

Un=ar^(n-1)

Where

a is first term

n is nth term

And r is common ratio

So in the question given above,

The third term exceed the first term by 16

i.e U3=U1+16

Where U1=a. First term

U3=a+16

Given also that, the sum if the third term and fourth term is 72.

Then U3+U4=72.

We are told to find common ratio (r)

U3=ar^3-1

U3=ar^2

Also, U4=ar^3

U3+U4=72

ar^2+ar^3=72

ar^2(1+r)=72. equation 1

Also for

U3=a+16

ar^2=a+16

ar^2-a=16

a(r^2-1)=16. From (x^2-y^2)=(x+y)(x-y)

Then,

a(r-1)(r+1)=16. Equation 2

Divide equation 2 by equation 1

a(r-1)(r+1)/ar^2(1+r) =16/72

Then a cancel a and (1+r) cancel (1+r)

So,

(r-1)/r^2=2/9

Cross multiply

9(r-1)=2r^2

2r^2-9r+9=0

Solving the quadratic equation

2r^2-6r-3r+9=0

2r(r-3)-3(r-3)=0

(r-3)(2r-3)=0

r-3=0. Or. 2r-3= 0

Then r=3 or r=3/2

8 0
3 years ago
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