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wlad13 [49]
3 years ago
15

Your rectangular garden is 15 1/2 feet long and 26.5 feet wide. You plan to build a border. The border material costs $2.88 for

1.5 feet in length. The border will be three bricks high. You contractor will charge you $420 for labor. What will be the total bill for the project? (show work thank you)
Mathematics
1 answer:
Elanso [62]3 years ago
3 0

Answer:

$ 903.84

Step-by-step explanation: First find the perimeter, width + length + width + length. Then multiply it by 3 as the border is 3 bricks tall, divide it by 1.5 then multiply by 2.88 to get the price of the border. Add $420 to get the final price.

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There are 160 children in a baseball league. 60% of those children are in middle school. How many children in the baseball leagu
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Answer: 96

Step-by-step explanation:

Take 160 divide by 100 and then multiply by 60.

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3 years ago
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The mean and standard deviation of a random sample of n measurements are equal to and ​, respectively. a. Find a ​% confidence i
marusya05 [52]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

33.55 <  \mu < 35.5

b

34.03 <  \mu < 34.969

c

Generally the width at  n =  49 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.952

     w =  1.904

Generally the width at  n =  196 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.4687

     w =  0.9374

d

The correct option is E

Step-by-step explanation:

From the question we are told  that

   The sample mean is  \= x  =  34.5

    The standard deviation is  s =  3.4

Generally given that the confidence level is 95% then the level of significance is  

       \alpha = (100 -  95)\%

=>     \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Considering question a

From the question  n  =  49

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{s }{\sqrt{n} }

=>   E = 1.96*  \frac{ 3.4 }{\sqrt{49} }

=>   E =  0.952

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  p <  \=x  +E

      34.5 -0.952 <  p < 34.5 + 0.952

=>    33.55 <  \mu < 35.5

Considering question b

From the question  n  =  196

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{s }{\sqrt{n} }

=>   E = 1.96*  \frac{ 3.4 }{\sqrt{196} }

=>   E =  0.4687

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  p <  \=x  +E

      34.5 -0.4687 <  p < 34.5 +0.4687

=>   34.03 <  \mu < 34.969

Considering question c

Generally the width at  n =  49 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.952

     w =  1.904

Generally the width at  n =  196 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.4687

     w =  0.9374

Now when the sample size is quadrupled i.e from n = 49 to  n =  196  

The width of the  confidence interval  decrease by 2 from 1.904 to  0.9374  

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4 • x = 44
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