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Maksim231197 [3]

4 years ago

11

The Peoples' Party was also known as the_______________.

1 answer:

Tomtit [17]4 years ago

5 0

<span>Populists should be tha answer

</span>

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The period known as Japan's "golden age of culture was most closely associated with

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What are the 2 SuperPowers for the Cold War

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The United States and the Soviet Union

Explanation:

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Three of the parties that began by splitting away from the two major political parties include the

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Why was Missouri's statehood so controversial?

blagie [28]

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Southerners who contradicted the Missouri Compromise did so since it set a point of reference for Congress to form laws concerning subjugation, whereas Northerners loathed the law since it implied servitude was extended into unused region. ... Sandford, which ruled that the Missouri Compromise was unlawful

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3 years ago

Help math Composite figures and there area please help number the questions please

vivado [14]

Answer:

1 of 5) D, 2 of 5) B, 3 of 5) D, 4 of 5) A, 5 of 5) D

Explanation:

1 of 5) The composite area is the sum of the areas of two rectangles. That is:

$A = (4\,cm)\cdot (3\,cm) + (6\,cm)\cdot (2\,cm)$

$A = 12\,cm^{2}+12\,cm^{2}$

$A = 24\,cm^{2}$

The area of the shaded region is 24 square centimeters. (Answer: D)

2 of 5) The composite area is the sum of the areas of the rectangle and the triangle. That is:

$A = (8\,cm)\cdot (5\,cm)+\frac{1}{2}\cdot (5\,cm)\cdot (5\,cm)$

$A = 40\,cm^{2} + 12.5\,cm^{2}$

$A = 52.5\,cm^{2}$

The area of the shaded region is 52.5 square centimeters. (Answer: B)

3 of 5) The composite area is the sum of the areas of the rectangle and the triangle. That is:

$A = (10\,cm)\cdot (4\,cm)+ \frac{1}{2}\cdot (7\,cm)\cdot (6\,cm)$

$A = 40\,cm^{2}+21\,cm^{2}$

$A = 61\,cm^{2}$

The area of the shaded region is 61 square centimeters. (Answer: D)

4 of 5) The composite area is the sum of the areas of four triangles and two rectangles. That is:

$A = 4\cdot \frac{1}{2}\cdot (1\,m)\cdot (2\,m) + (8\,m)\cdot (4\,m)+(3\m)\cdot (1\,m)$

$A = 4\,m^{2}+32\,m^{2}+3\,m^{2}$

$A = 39\,m^{2}$

The area of the shaded region is 39 square meters. (Answers: A)

5 of 5) The composite area is the sum of the areas of the three semicircles and the square. That is:

$A =3\cdot \frac{\pi}{8}\cdot (10\,cm)^{2}+ (10\,cm)^{2}$

$A = 117.810\,cm^{2}+100\,cm^{2}$

$A = 217.810\,cm^{2}$

The area of the shaded region is 217.810 square centimeters. (Answer: D)

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3 years ago

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