Answer:
2y^32
Step-by-step explanation:
Since 2^8 = 256, the eighth root of 256 is 2.
Next, we find the power of y by multiplying 256 and 1/8: result is 32.
Complete answer: 2y^32
Answer:

Step-by-step explanation:
<u>Extended Information </u><u>on</u><u> </u><u>the</u><u> Complex Number System</u>
![\displaystyle \sqrt{-1} = i \\ -1 = i^2 \\ -i = i^3 \\ 1 = i^4\:[all\:multiples\:of\:four]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B-1%7D%20%3D%20i%20%5C%5C%20-1%20%3D%20i%5E2%20%5C%5C%20-i%20%3D%20i%5E3%20%5C%5C%201%20%3D%20i%5E4%5C%3A%5Ball%5C%3Amultiples%5C%3Aof%5C%3Afour%5D)
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All work is shown above. ↑
start by plugging in the value you already have, in this case, 5 for y.
-4x-3(5)=17
-4x-15=17
-4x=32
x=-8
however, since a is a+1, a would be 7 (making x 8)
also plz tell me if i read this wrong and it’s actually 1,5 rather than a+1 and 5 cause if i did i’m so sorry lol.