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Alina [70]
3 years ago
7

Thing Fill in the blank with the correct response. The slope of the graph of y= 5x is ao

Mathematics
2 answers:
Vika [28.1K]3 years ago
7 0
The slope is 5.

In slope intercept form, y=mx+b, m is the slope. You can see that 5 is in the place of m, so the slope is 5
ch4aika [34]3 years ago
3 0

Answer:

slope is 5

Step-by-step explanation:

y = 5x

This is in the form

y = mx+b where m is the slope and b is the y intercept

The slope is 5 and the y intercept is 0

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What is the solution to |x – 5| + 2 < 20?
stepladder [879]

Answer:

Step-by-step explanation:

hello :

|x – 5| + 2 < 20  means :  |x – 5| + 2-2 < 20-2

|x – 5|  < 18

-18< x - 5 < 18

-18+5< x - 5+5 < 18+5

-13< x< 23   ( solutions)

3 0
2 years ago
Solve 4x + 5 = x + 26​
prohojiy [21]

Answer:

Step-by-step explanation: 7

Subtract 5 on both sides to get 4x = x + 21

then, subtract x from 4x and x is 1, so 3x = 21 then divide by 3 on both sides

8 0
3 years ago
Read 2 more answers
Whats the answer? Well the length of the arc
bagirrra123 [75]
Your answer would be 35 because whatever the angle is that is what the arc length would be.
4 0
3 years ago
The variable x varies directly as the cube of y, and y varies directly as the square root of z. If x equals 1 when z equals 4, w
Aloiza [94]

Answer:

<h2>z=36</h2>

Step-by-step explanation:

According to the question,

x∝y^3          .......(1)

y∝\sqrt{z}    .......(2)

From equation 1,2 let constant of proportionality be k1,k2 respectively.

⇒x=k1(y^3)            .......(3)

⇒y=k2(\sqrt{z} )    .......(4)

From the above equations putting 4 into 3,

x=k1((k2\sqrt{z})^3) =k1.k2^3.(\sqrt{z})^3

Let the new constant to the above equation be k3,

x=k3(\sqrt{z})^3

Given,if x=1, when z=4

1=k3(\sqrt{4} )^3=k3(8)

⇒k3=\frac{1}{8}

Now if x=27, then z=?

27=\frac{1}{8} (\sqrt{z} )^3

⇒(\sqrt{z} )^3=27(8)

⇒\sqrt{z}=3(2)=6

z=36

4 0
3 years ago
What is the domain and range of each relation?
LUCKY_DIMON [66]

Answer:

\text{Domain of}R_1=\{-2,0,2,4\}  and \text{Range of}R_1=\{-3,-1,0\}

\text{Domain of}R_2=\{-3,-1,0,3\}  and \text{Range of}R_2=\{-1,0,1,2,3\}

Step-by-step explanation:

Domain is the set of input values or x-values.

Range is the set of output values or y-values.

According to the relation mapping diagram, the relation is

R_1=\{(-2,-3),(-2,-1),(0,0),(2,0),(4,-3)\}

So,

\text{Domain of}R_1=\{-2,0,2,4\}

\text{Range of}R_1=\{-3,-1,0\}

In the graph 5 points are plotted. So, the relation is  

R_2=\{(-3,1),(-1,-1),(0,0),(3,2),(3,3)\}

So,

\text{Domain of}R_2=\{-3,-1,0,3\}

\text{Range of}R_2=\{-1,0,1,2,3\}

4 0
3 years ago
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