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3 years ago

Thing Fill in the blank with the correct response. The slope of the graph of y= 5x is ao

2 answers:

7 0

The slope is 5.

In slope intercept form, y=mx+b, m is the slope. You can see that 5 is in the place of m, so the slope is 5

ch4aika [34]3 years ago

3 0

Answer:

slope is 5

Step-by-step explanation:

y = 5x

This is in the form

y = mx+b where m is the slope and b is the y intercept

The slope is 5 and the y intercept is 0

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What is the solution to |x – 5| + 2 < 20?

stepladder [879]

Answer:

Step-by-step explanation:

hello :

|x – 5| + 2 < 20 means : |x – 5| + 2-2 < 20-2

|x – 5| < 18

-18< x - 5 < 18

-18+5< x - 5+5 < 18+5

-13< x< 23 ( solutions)

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2 years ago

Solve 4x + 5 = x + 26

prohojiy [21]

Answer:

Step-by-step explanation: 7

Subtract 5 on both sides to get 4x = x + 21

then, subtract x from 4x and x is 1, so 3x = 21 then divide by 3 on both sides

8 0

3 years ago

Read 2 more answers

Whats the answer? Well the length of the arc

bagirrra123 [75]

Your answer would be 35 because whatever the angle is that is what the arc length would be.

4 0

3 years ago

The variable x varies directly as the cube of y, and y varies directly as the square root of z. If x equals 1 when z equals 4, w

Aloiza [94]

Answer:

Step-by-step explanation:

According to the question,

$x$ ∝ $y^3$ .......(1)

$y$ ∝ $\sqrt{z}$ .......(2)

From equation 1,2 let constant of proportionality be $k1,k2$ respectively.

⇒ $x=k1(y^3)$ .......(3)

⇒ $y=k2(\sqrt{z} )$ .......(4)

From the above equations putting 4 into 3,

$x=k1((k2\sqrt{z})^3) =k1.k2^3.(\sqrt{z})^3$

Let the new constant to the above equation be $k3$ ,

$x=k3(\sqrt{z})^3$

Given,if x=1, when z=4

$1=k3(\sqrt{4} )^3=k3(8)$

⇒ $k3=\frac{1}{8}$

Now if x=27, then z=?

$27=\frac{1}{8} (\sqrt{z} )^3$

⇒ $(\sqrt{z} )^3=27(8)$

⇒ $\sqrt{z}=3(2)=6$

$z=36$

4 0

3 years ago

What is the domain and range of each relation?

LUCKY_DIMON [66]

Answer:

$\text{Domain of}R_1=\{-2,0,2,4\}$ and $\text{Range of}R_1=\{-3,-1,0\}$

$\text{Domain of}R_2=\{-3,-1,0,3\}$ and $\text{Range of}R_2=\{-1,0,1,2,3\}$

Step-by-step explanation:

Domain is the set of input values or x-values.

Range is the set of output values or y-values.

According to the relation mapping diagram, the relation is

$R_1=\{(-2,-3),(-2,-1),(0,0),(2,0),(4,-3)\}$

So,

$\text{Domain of}R_1=\{-2,0,2,4\}$

$\text{Range of}R_1=\{-3,-1,0\}$

In the graph 5 points are plotted. So, the relation is

$R_2=\{(-3,1),(-1,-1),(0,0),(3,2),(3,3)\}$

So,

$\text{Domain of}R_2=\{-3,-1,0,3\}$

$\text{Range of}R_2=\{-1,0,1,2,3\}$

4 0

3 years ago