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8 0

3 years ago

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ABCD, GB is parallel to AK, AC is congruent to DB, GB is perpendicular to BD, KC is perpendicular to AC

AleksandrR [38]

Answer:

The two column proof is given as follows;

Statement ${}$ Reason

1. $\overline {ABCD}$ , $\overline{GD}$ \\ $\overline {AK}$ , $\overline{AC}$ ≅ $\overline {DB}$ ${}$ Given

$\overline{GB}$ ⊥ $\overline {BD}$ , $\overline{KC}$ ⊥ $\overline {BD}$

2. ∠KCA = ∠GBD = 90° ${}$ Given

3. Therefore,

4. ∠KAB = ∠GDC ${}$ Alternate interior angles

5. ΔGBD ≅ ΔKCA ${}$ By ASA rule of congruency

6. $\overline{GB}$ ≅ $\overline {KC}$ ${}$ By CPCTC

Explanation:

Given that two angles and an included side of triangle ΔGBD are equal to the corresponding two angles and an included side of triangle ΔKCA, therefore, ΔGBD ≅ ΔKCA by the Ange-Side-Angle rule of congruency, therefore, we have;

Segment $\overline{GB}$ is congruent to segment $\overline {KC}$ by Congruent Parts of Congruent Triangles are Congruent, CPCTC.

6 0

3 years ago

If the sin 0° = 0, then which statement is true? (6 points) cos 90° = 1, because the cosine and sine are complements cos 180° =

DedPeter [7]

Answer:

cos 90° = 0, because the angles are complements

Explanation:

Complementary angles are those angles whose angles are sum up to 90 degrees that we called right angles

Just like

one angle is 45 degrees

And, the other angles are also 45 degrees

So, the sum of both two angles are 90 degrees

Now if

sin 0° = 0

The cos 0° = 0 as the angles are considered to be the complement

We used the equation as shown below:

$sin{\theta} = cos (90 - {\theta})$

8 0

3 years ago