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3 years ago

What is the answer to 3 2/5÷4 1/3

1 answer:

3 0

3 and 2/5 ÷ 4 and 1/3
The first step before you can divide these is that you must make them improper fractions, they cannot be mixed numbers.

3 = 3/1 = 15/5
15/5 + 2/5 = 17/5
3 and 2/5 = 17/5

4 = 4/1 = 12/3
12/3 + 1/3 = 13/3
4 and 1/3 = 13/3

Now you can divide 17/5 and 13/3.

Step 1- Turn the fraction you are dividing by into its reciprocal.
13/3 reciprocal equals 3/13

Step 2- Multiply.
17/5 • 3/13
17 • 3 = 51
5 • 13 = 65
Answer: 51/65

Step 3- Simplify if possible.
51/65
This is already in simplest form so there is no need to simplify.

So the answer is 51/65.

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3 years ago

Read 2 more answers

The graphs of two rational functions of f and g are shown. One of them is given by the expression 2-3x/x. Which graph is it? Tha

Nesterboy [21]

Answer:

It's the left graph, y = f(x)

Step-by-step explanation:

If you find the x-intercepts, you'd solve (2-3x)/x = 0. This means you'd really solve 2-3x=0, which gives you x=3/2.

So the graph must have an x-intercept at (1.5, 0). Only f(x) has that.

8 0

2 years ago

Jamal's deck is in the shape of a polygon and is shown on the grid below.(-8,6)(6,6)o[(-8, -4),(6,-4)What is the area of Jamal's

PSYCHO15rus [73]

Let;

A(-8,6) B(6,6) C(6, -4) D(-8, -4)

Let's find the length AB

x₁= -8 y₁=6 x₂=6 y₂=6

We will use the distance formula;

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

$=\sqrt[]{(6+8)^2+(6-6)^2}$ $=\sqrt[]{14^2+0}$ $=14$

Next, we will find the width BC

B(6,6) C(6, -4)

x₁= 6 y₁=6 x₂=6 y₂=-4

substitute into the distance formula;

$d=\sqrt[]{(6-6)^2+(-4-6)^2}$

$=\sqrt[]{(-10)^2}$ $=\sqrt[]{100}$ $=10$

Area = l x w

= 14 x 10

= 140 square units

7 0

1 year ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

3 years ago

PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the

stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

3 0

3 years ago