Explanation:
The problem says that the hairless phenotype never breeds true. That means that it's not the result of a homozygous genotype (H₁H₁ or H₂H₂), so it is caused by the heterozygous genotype (H₁H₂).
The <u>expected </u>offspring from the cross between two Mexican hairless would be:
<h3>P
H₁H₂ x
H₁H₂</h3><h3>F1 1/4
H₁H₁, 2/4
H₁H₂ and 1/4
H₂H₂.</h3>
And the <u>expected</u> phenotypic ratio 3:1. However, the observed offspring shows a 2:1 ratio. What's happening?
If the observed phenotypic ratio in the offspring of a monohybrid cross (a single gene with two alleles) is 2:1, we can suspect that one of the genotypes is lethal in homozygosis and therefore does not appear in the progeny (the puppies are born dead).
If we proposed that the H₂ allele is lethal in homozygosis, then:
- The H₁H₁ genotype would cause normal puppies --> 1
- The H₁H₂ genotype would cause hairless puppies --> 2
- The H₂H₂ is lethal and causes the death of puppies --> 0
The phenotypic ratios change to 2:1, as observed in the experiment.
Why dies???? what do you mean
The answer to this question would be soft agar plate.
The semisolid medium tube is mostly used for containing the specimen. It is hard to examine semisolid medium since the bacteria can grow in the upper part, middle part or even the lower part of the medium. In agar plate, the bacteria always growth in the upper part so it is easier to count the bacteria.
But semisolid can give some more information in determining whether the bacteria is anaerobic by looking for bubble inside the medium. Anaerobic bacteria can do fermentation that will produce air.
Answer:
CGTTAAGCGATAGCATCC
Explanation:
remember A always pairs with T and G always pairs with C. you can also remember them as Apple Tree and Car Garage.
hope this helps :)
C) I and III only just got this question on usa test prep and therefore i'm right
