To find the equation of a line that is parallel to your original equation and goes through a certain point on a graph, here's what you need to know:
First you need to find the slope of your original equation.
To do that, you need to convert it to slope intercept form (y = mx+b).
Add the x over, and then divide everything by 5 to get the y by itself.
Here's what that would look like (without the small steps that I mentioned):
-x + 5y = 25
5y = x + 25
y = 1/5x + 5
That's the original equation rewritten in slope intercept form.
The m represents the slope, so this equation's slope is 1/5.
Because you are given a point, and now you have a slope, the best and easiest route is using point slope form.
I've seen different versions of the equation base but I prefer y - y(sub1) = m(x - x(sub1))
But since I can't use subscripts in this, I'll use the one with h and k. The h is the x value of the point, and the k is the y value.
(h,k)
Then just substitute the values in and solve for y.
y - k = m(x - h)
y + 5 = 1/5(x + 5)
y + 5 = 1/5x + 1
y = 1/5x - 4
Your final answer is
y = 1/5x - 4
You can double check by using a graph. If the slopes are the same, the lines should be parallel.
I hope that helps. If anything didn't make sense, feel free to ask me.
Step-by-step explanation:
sinx=20/36
x=sin-¹20/36
x=34
Answer: 3/8
Step-by-step explanation:
When three coins are flipped, we get 8 total outcomes: (HHH,HHT,HTH,HTT,THH,THT,TTH,TTT)
Two tails and one head is (HTT, TTH, THT)
Probability = number of favorable outcomes/ number of total outcomes
Number of Favorable outcomes = 3
Number of Total outcomes= 8
Therefore, probability of getting 2 tails and one head
= 3/8
The Rome data center is best described by the mean. The New York data center is best described by the median. The third option C is correct.
<h3>The Mean and Median:</h3>
The mean of a data set is the average of all the terms in the data set. The median of a data set is the value of the midpoint term in the frequency distribution.
From the given information, the table can be better expressed as:
High Low Q1 Q3 IQR Median Mean σ
Rome 18 1 3 7 4 6.5 6.4 4.3
NY 14 1 4.5 8.5 4 5.5 6.1 3.2
- From the data sets in the table, the distribution for Rome is not largely diverse, and there isn't much departure from the mean value. It indicates that in the data set of Rome families, no outliers have occurred.
- In New York, the data indicate a distinct outlier for New York families in Q3. This is due to the fact that the gap is so large, the mean may not be a good choice for determining the measure of the central tendency.
Therefore, we can conclude that, the Rome data center is best described by the mean and the median will be utilized to determine the central tendency in New York.
Learn more about mean and median here:
brainly.com/question/14532771
