You want to estimate the population proportion of pine trees over 90 years old in a forest near where you live. You need a margi
n of error of no more than 2%. With no more information to go on, what's the simplest formula for calculating your minimum sample size? n equals open parentheses fraction numerator z asterisk times over denominator m end fraction close parentheses squared bullet P to the power of asterisk times open parentheses 1 minus P to the power of asterisk times close parenthesesA.
a. n equals open parentheses fraction numerator t asterisk times over denominator 2 m end fraction close parentheses squaredB.
b. n equals open parentheses fraction numerator z asterisk times over denominator m end fraction close parentheses squared bullet P open parentheses 1 minus P close parenthesesC.
c. n equals open parentheses fraction numerator z asterisk times over denominator 2 m end fraction close parentheses squaredD.
d. Can't Be Determined E.
Minimum sample size for estimating the population proportion of pine trees over 90 years old in a forest near where you live with <em>margin of error</em> no more than 2% can be calculated using the equation:
n≥ p×(1-p) × where
n is the sample size
p is the proportion of pine trees over 90 years old in a forest near where you live
z is the corresponding z-score for the confidence level
ME is the margin of error in the estimation (2% or 0.02)
