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melomori [17]
3 years ago
6

789/548x-89/887=688/8724 find x

Mathematics
1 answer:
Olin [163]3 years ago
8 0

\frac{789}{548}x- \frac{89}{887}=\frac{688}{8724}

first we try to semplify as much as possible the fractions.

First we decompose the numbers

789 = 3 * 263

548 = 2 * 2 * 137 = 2^2

they have nothing in common, so the first fraction remains so

89 = 89 (prime number)

887 = 887 (prime number)

they have nothing in common, so the second one remains so

688 = 2 * 2 * 2 * 2 * 43 = 2^4 * 43

8724 = 2 * 2 * 3 * 727 = 2^2 * 3 * 727

they have 2^2 (=4) in common, so the numerator and the denominator can be devided by 4

\frac{688}{8724}= \frac{688:4}{8724:4}=\frac{172}{2181}

so:

\frac{789}{548}x- \frac{89}{887}=\frac{172}{2181}

now we calculate the common denominator

take the scomposition:

548 = 2^2 * 137

887 = 887

2181 = 3 * 727

take every number one time

so the common denominator is 2^2 * 137 * 887 * 727 * 3 = 1'060'131'756

now calculate every single numerator: first we divide each denominator by the common denominator, then we moltiply the result with each numerator

first fraction: 789/548

1060131756 / 548 = 1934547

1934547 * 789 = 1526357583

second fraction: 89/887

1060131756 / 887 = 1195188

1195188 * 89 = 106371732

third one: 172/2181

1060131756 / 2181 = 486076

486076 * 172 = 83605072

now we can delete the common denominator

1526357583x - 106371732 = 83605072

solve it

1526357583x = 83605072 + 106371732

1526357583x = 189976804

x = 1526357583 / 189976804

decompose

1526357583 = 887 * 3 * 3 * 727 * 263

189976804 = 137 * 2 * 2 * 211 * 53 * 31

nothing in common

x = 1526357583 / 189976804

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Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

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(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

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Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

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