Question

PLEASE HELP WILL MARK BRAINLIEST Write the equation of the line parallel to the given line and passing through the given point. 6x+y=4 through (−2,3)

Answer 1

The parallel lines have the same slope.

The slope-intercept form: y = mx + b

m - a slope.

We have 6x + y = 4     |subtract 6x from both sides

y = -6x + 4 → m = -6.

The slope-point form:

$y-y_1=m(x-x_1)$

We have m = -6 and (-2, 3).

Substitute:

$y-3=-6(x-(-2))\\\\y-3=-6(x+2)\\\\y-3=(-6)(x)+(-6)(2)\\\\y-3=-6x-12\qquad|+3\\\\y=-6x-9\qquad|+6x\\\\6x+y=-9$

Answer: 6x + y = -9.