Answer:
The second city is 54 miles behind the first city
Step-by-step explanation:
The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.
The speed of the second bus is then 54/0.6 = 90 mph
When 1 and a half hour has passed, the first bus has moved a distance of
= 81 miles
The second bus (behind the first bus) has moved
= 135 miles
The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city
So, the second city is 54 miles behind the first city
Answer:
12(6+9m)
therefore we multiple the 12 by the numbers in the blaket
72+10m
that's the correct answer
Answer:
C) 3
Step-by-step explanation:
Let us say that the numbers are x and y. The given clues
are:
1. x – y = 16 (so
x is the larger number)
2. y / x = 5 / 7
rewriting eqtn 2 in terms of y:
y = (5/7) x
combining 1 and 2:
x – (5/7) x = 16
(2/7) x = 16
x = 56
y = (5/7) x = 40
So the two numbers are 56 and 40.
1 hr plus 20 minutes
Then that answer divided by 15
Then that answer multiply by 3/4