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LekaFEV [45]
4 years ago
5

In a bag of blue and yellow marbles, the ratio of blue marbles to yellow marbles is 3:5. if the bag contains 60 yellow marbles,

how many blue marbles are there?
Mathematics
1 answer:
fiasKO [112]4 years ago
4 0
Double the numbers by themselves for 5 times and you get the ration of blue to yellow balls of 96:60
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PLEASEHELP!
denis-greek [22]
You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5

100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10

6 0
3 years ago
Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past
blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0
3 years ago
It hard I need help can y’all help me plz
KatRina [158]

Answer:

we dont have a question or picture..?

7 0
3 years ago
Mona wrote 7 tests, and her test average is 93. There will be one more test before the end of the year. What is the lowest grade
olga55 [171]
For this case, the first thing we are going to do is assume that all the tests are worth the same.
 Then, we define a variable:
 x: score of Mona's last test
 We write now the inequality that models the problem:
 \frac{93 + x}{2}  \geq  90
 From here, we clear the value of x: 93 + x  \geq  90*(2) 

93 + x  \geq  180

 x  \geq  180 - 93

 x  \geq  87
 Answer:
 
the lowest grade that Mona can get for her last test so that her test average is 90 or more is:
 
x = 87
8 0
3 years ago
2^x times 3^x<br><br> Work out the value of x
kumpel [21]
6^x is 3×2 is six I hope I've helped you
3 0
3 years ago
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