Answer:
73 and 15
Step-by-step explanation:
I made two variables for this:
x = larger number
y = smaller number
Write an equation for "the sum of two number is 88" and you get:
x + y = 88
Write an equation for "four times the smaller number is subtracted from the larger number" and you get:
x - 4y = 13
I do not want an equation with both x and y in it, so I will rewrite the first one and use substitution in the second one:
x + y = 88 -- move the x to the other side
y = 88 - x
x - 4y = 13 -- substitute for y
x - 4(88 - x) = 13 -- multiply by 4
x - 352 + 4x = 13 -- move -352 to the other side, combine x's
5x = 365 -- divide by 5
x = 73
Now that I know x is 73, I go back to my first equation (x + y = 88) and I get:
73 + y = 88 -- subtract 73 from both sides
y = 88 - 73
y = 15
Y=1x+(-5) because the y-intercept is negative 5 and that is going to be the B value. Because anything that multiplies with zero equals zero so when you input 0 for x the b value would always be the y-intercept.
Well to solve these type of question it is very easy to make a tree diagram and then solve them. How ever i have done it here for you.
So basically we have to get a pen from the first box so its probability is 7 / 10.
Similarly, we have to get a crayon from the second box so its probability is 2 / 8.
Now by counting principle we can multiply the two probabilities so 7/10 * 1/4 which becomes equal to 7/40.
<u>X - Intercept</u>
x + 3y + 2z = 6
x + 3(0) + 2(0) = 6
x + 0 + 0 = 6
x + 0 = 6
<u> - 0 - 0</u>
x = 6
X - Intercept: (6, 0, 0)
<u>Y - Intercept</u>
x + 3y + 2z = 6
0 + 3y + 2(0) = 6
0 + 3y + 0 = 6
0 + 0 + 3y = 6
0 + 3y = 6
<u>- 0 - 0</u>
<u>3y</u> = <u>6</u>
3 3
y = 2
Y - Intercept: (0, 2, 0)
<u>Z - Intercept</u>
x + 3y + 2z = 6
0 + 3(0) 2z = 6
0 + 0 + 2z = 6
0 + 2z = 6
<u>- 0 - 0</u>
<u>2z</u> = <u>6</u>
2 2
z = 3
Z - Intercept: (0, 0, 3)
<u>Volume of the X - Intercept, Y - Intercept, and Z - Intercept</u>
V = ¹/₃(¹/₂lwh)
V = ¹/₃(¹/₂(6)(2)(3))
V = ¹/₃(¹/₂(12)(3))
V = ¹/₃(¹/₂(36))
V = ¹/₃(18)
V = 6 u³
Answer:
100
Step-by-step explanation:
2(5)^2
10^2
100
