The total weight of Mason is 177
<em><u>Solution:</u></em>
Given that, Mr.Mason takes two-thirds of his body weight and drinks that amount of gatorade in ounces per day
Mr.Mason drinks 118 ounces each day
Let "x" be the total weight of Mr.Mason
Therefore, we can say,
Two third of body weight = Amount of gatorade drank in ounces per day
Two third of x = 118
Thus total weight of Mason is 177
(a)
The probability is : 1/2
(b)
The probability is : 1/2
<h2>Step-by-step explanation:</h2>The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.
The total combinations that are possible are:
(1,2) (1,3) (1,4) (1,5)
(2,1) (2,3) (2,4) (2,5)
(3,1) (3,2) (3,4) (3,5)
(4,1) (4,2) (4,3) (4,5)
(5,1) (5,2) (5,3) (5,4)
i.e. the total outcomes are : 20
(a)
Let A denote the event that the first number is 4.
and B denote the event that the sum is: 9.
Let P denote the probability of an event.
We are asked to find:
P(A|B)
We know that it could be calculated by using the formula:
Hence, based on the data we have:
( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )
and
( since, there are just two outcomes such that the sum is: 9
(4,5) and (5,4) )
Hence, we have:
(b)
Let A denote the event that the first number is 3.
and B denote the event that the sum is: 8.
Let P denote the probability of an event.
We are asked to find:
P(A|B)
Hence, based on the data we have:
( since, the only outcome out of 20 outcomes is: (3,5) )
and
( since, there are just two outcomes such that the sum is: 8
(3,5) and (5,3) )
Hence, we have: