Question

- 2x + 5y = -15 How many solutions does the system have? V exactly one The solution to the system is 5x + 2y = -6 How could you solve this system using elimination? Check all that apply. * Multiply the first equation by 2 and the second equation by 5, then add. Multiply the first equation by 5 and the second equation by 2. Then add. Multiply the first equation by 2 and the second equation by 5, then subtract. Multiply the first equation by 5 and the second equation by 2, then subtract.

Answer 1

Answer:

Multiply the first equation by 5 and the second equation by 2. Then add.

Multiply the first equation by 2 and the second equation by 5, then subtract.

Step-by-step explanation:

Given

$- 2x + 5y = -15$

$5x + 2y = -6$

Required

Steps to solve using elimination method

From the list of given options, option 2 and 3 are correct

This is shown below

Option 2

Multiply the first equation by 5

$5(- 2x + 5y = -15)$

$-10x + 25y = -75$

Multiply the second equation by 2.

$2(5x + 2y = -6)$

$10x + 4y = -12$

Add

$(-10x + 25y = -75) + (10x + 4y = -12)$

$-10x + 10x + 25y +4y = -75 - 12$

$29y = -87$

Notice that x has been eliminated

Option 3

Multiply the first equation by 2

$2(- 2x + 5y = -15)$

$-4x + 10y = -30$

Multiply the second equation by 5

$5(5x + 2y = -6)$

$25x + 10y = -30$

Subtract.

$(-4x + 10y = -30) - (25x + 10y = -30)$

$-4x + 25x + 10y - 10y= -30 +30$

$21x = 0$

Notice that y has been eliminated

Answer 2

Answer:

How many solutions does the system have?

✔ exactly one

The solution to the system is

(

⇒ 0,

⇒ -3).

Step-by-step explanation:

the next two parts