Answer:
1000 times
Step-by-step explanation:
Given:
The Sun is roughly 10^2 times as wide as the Earth.
The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.
Question asked:
About how many times as wide as the Sun is KW Sagittarii?
Solution:
Let the width of the earth = 
As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun = 
And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = 
Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:
Width of the Star KW Sagittarii = 
Width of the Sun = 

x canceled by x

Therefore, Star KW Sagittarii is 1000 times wider than Sun.
<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>
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Answer:
x = 70°
Step-by-step explanation:
Itz given that AB & CD are perpendicular to each other and intersect at E . So , angle(AED) = 90°
But here the value of angle(AED) = 90°
So,
x + 20 = 90°
=> x = 90° - 20°
= 70°
2q+18=-5q-3
2q+5q=-3-18
7q=-21
q=-3
Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
For the first one, it would be 5/3 and 19/3
the second one would be 40