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timurjin [86]
4 years ago
8

Which expressions are equivalent to the given expression?√252 more than one answer

Mathematics
1 answer:
DochEvi [55]4 years ago
3 0
15.87 or 15.8 that’s from me finding the square root if that helps any
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Please help ASAP! I will mark Brainliest! Please answer CORRECTLY! No guessing! CHECK ALL THAT APPLY
Mashutka [201]

Answer:

0,8,5

Step-by-step explanation:

x+22 <32

Subtract 22 from each side

x+22-22 <32-22

x <10

The choices that fit

0,8,5

8 0
3 years ago
Read 2 more answers
Make the eqaution equal 4,416 for alot of points
irga5000 [103]

Answer:

2 *( 3+7-9) =(1+5) - ( 8 -4 )

Step-by-step explanation:

2 _( 3_7_9) = (1_ 5) _ ( 8 _4 )

I just started playing with things

2 *( 3+7-9) = (1_5 ) _ ( 8 _4 )

2 * (10-9)

2*1

So the left side is 2

Now to make the right side 2

(1+5) - ( 8 -4 )

6 - 4

2

4 0
3 years ago
Read 2 more answers
Help me please I all ready submit all my question on my profile go see it it is due right now I will mark you as a brainlest rig
pashok25 [27]

Answer:

ok

Step-by-step explanation:

6 0
3 years ago
Why is every prime number greater than 2 an odd number?
DanielleElmas [232]
Every prime greater than 2 is oddNo even number greater than 2 is prime
5 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
4 years ago
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