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shtirl [24]
3 years ago
11

What is 3 1/3 divided by 1 7/8 in simplest form ?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0
You have to turn them into mixed numbers.  10/3 divided by 15/8.  Now you have to multiply the first number by the reciprocal of the second.  10/3 times 8/15.  The answer is 80/45 or 1 7/9.
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Identify the factors of the terms of the expression. <br>3). 5+6a+11b<br>4). 13m-2n​
xeze [42]

Answer:

factors are 5, 6, a, 11, b

Step-by-step explanation:

3)   5 + 6a + 11b

<u>Algebraic expressions: 5 + 6a + 11b </u>

Are combinations of numbers, variables, and at least one arithmetic.

<u>Term are: 5, 6a, 11b</u>

Each expression is made up of terms. A term can be a signed number, a variable, or a constant multiplied by a variable(s).

<u>Factors are: 5, 6, a, 11, b </u>

Something which is multiplied by something else. A factor can be a variable, number,  a term, or a longer expression.

<u>Coefficient: 6, 11 </u>

The numerical factor of a multiplication expression that contains a variable.

 

<u>Constant: 5 </u>

A number that cannot change its value.

4).  13m-2n​ (note: it applies as above)

7 0
3 years ago
How do you solve these math questions?? I really really need help!!
Dmitry [639]
I surely don't have any clue on how to that type of math sorry.
6 0
3 years ago
What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64
marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are 2x+y\geq 8 -------(1)

x+y \geq 6   ------------- (2)

x \geq 0, y \geq 0  -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, 2\times 0+0\geq 8⇒0\geq 8 ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, 0+0\geq 6⇒0\geq 6 ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4),  C= 46

At B≡(6,0),  C= 42

Thus at B, C is minimum, And its minimum value = 42


5 0
3 years ago
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alexandr1967 [171]

Answer:

1/4

Step-by-step explanation:

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