Solve for p: p + 2x = 4

Lolll I need help again! URGENT!!!!

Mars2501 [29]

Every time you get 6 times out of 8 you times it like 12 16,18 24

8 0

3 years ago

Your friend is 1.2 times taller than you. Your friend is 64.5 inches tall. How tall are you?

Andru [333]

You are X, if your friend is 1.2 times taller than you= 1.2X
That's why 64.5=1.2X
X=53.75
But you should write 53.8 inches tall. Because there is one number after point.
<span>As a result, you are 53.8 inches tall

</span>

6 0

2 years ago

A coat has been marked down 20% to $26.40 what was it's original value?

Gemiola [76]

20% is equal to 0.2
0.2 times 26.40 is equal to 5.28
26.40 minus 5.28 is equal to 21.12

6 0

2 years ago

Based on the data in the two-way table, what is the probability that a person weighs 120 pounds, given that he or she consumes 2

sdas [7]

<span>In the question "Based on the data in the two-way table, what is the probability that a person weighs 120 pounds, given that he or she consumes 2,000 to 2,500 calories per day?" The probability of an event, say A given another event, say B is given by n(A and B) / n(B). Thus the probability that a person weighs 120 pounds, given that he or she consumes 2,000 to 2,500 calories per day is given by number of persons that weigh 120 pounds and consume 2,000 to 2,500 calories per day / number of persons that consume 2,000 to 2,500 calories per day. From the table, the number of persons that weigh 120 pounds and consume 2,000 to 2,500 calories per day is 10 while the number of persons that consume 2,000 to 2,500 calories per day is 110. Therefore, the required probability is 10 / 110 = 1 / 11</span>

3 0

3 years ago

Read 2 more answers

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

2 years ago