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vodka [1.7K]
3 years ago
10

Solve for v. 5v- 13=22

Mathematics
2 answers:
aliina [53]3 years ago
7 0

Answer:

5(7)-13=22

Step-by-step explanation:

siniylev [52]3 years ago
3 0

Answer:

7

Step-by-step explanation:

5v-13=22

   +13  +13

5v=35

5v/35

v=7

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Explain how you would subtract -4/5 from 9/10 .
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Answer:

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Step-by-step explanation:

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then you have to mutiply -4/5 by 2 which would be -8/10

and then you would do regular subtraction

but since its a negative number your gonna actually add but then the final answer will be negative

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hope this helps I really suck with fractions

4 0
3 years ago
Find the values of the variables
kogti [31]
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4 0
4 years ago
Find the area of the trapezoid
Cloud [144]

Answer:

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Step-by-step explanation:

hope that helps.

6 0
3 years ago
Suppose in Loma, Montana the temperature rose from -2.3 degrees Fahrenheit to 8.6 degrees Fahrenheit. What is the change in temp
adelina 88 [10]

Answer:

A: 10.9

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6 0
3 years ago
How do I verify the identity: sec(t)+1/tan(t)=tan(t)/sec(t)-1
kompoz [17]
\bf \textit{Pythagorean Identities}
\\ \quad \\
sin^2(\theta)+cos^2(\theta)=1
\\ \quad \\
1+cot^2(\theta)=csc^2(\theta)
\\ \quad \\
\boxed{1+tan^2(\theta)=sec^2(\theta)}\implies tan^2(\theta)=sec^2(\theta)-1\\\\
-----------------------------\\\\
\cfrac{sec(x)+1}{tan(x)}=\cfrac{tan(x)}{sec(x)-1}\\\\
-----------------------------\\\\

\bf \cfrac{sec(x)+1}{tan(x)}\cdot \cfrac{sec(x)-1}{sec(x)-1}\impliedby \textit{using the conjugate}\\\\
-----------------------------\\\\
recall\qquad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
thus\qquad \cfrac{sec^2(x)-1^2}{tan(x)sec(x)-1}\implies \cfrac{sec^2(x)-1}{tan(x)sec(x)-1}
\\\\\\
\cfrac{\underline{tan^2(x)}}{\underline{tan(x)} sec(x)-1}\implies \cfrac{tan(x)}{sec(x)-1}
4 0
4 years ago
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