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Marat540 [252]
3 years ago
7

A rectangular bathtub is 5 1/2 feet long, 1 1/2feet wide, and 3 feet high. Daniel fills the tub to a depth of 2feet.What is the

volume of the water in the tub?
Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0
To find the volume of the water that is in the tub, you will multiply the length by the wet by the height/depth of the water.

V = lwh
5 1/2 x 1 1/2 x 2
V = 16 1/2 ft.³

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Answer:

x = - 1

Step-by-step explanation:

Given

- 4(3x - 7) = 40 ( divide both sides by - 4 )

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D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
3 years ago
Consider the function represented by 9x + 3y= 12 with x as the independent variable. How can this function be written
Elena-2011 [213]

Answer: f(x) = -3x + 4

Step-by-step explanation:

The function is represented by

9x + 3y= 12

This is a linear equation with x as the independent variable. This means that if x is the independent variable, the y is the dependent variable. The values of y depends on the values of x. In order to represent the function, 9x + 3y= 12, we would rearrange the function such that y stands alone on the left hand side of the equation. This becomes

9x + 3y= 12

Subtracting 9x from both sides,

9x -9x + 3y = 12 - 9x

3y = 12-9x

Dividing the lefthand side and right hand side of the equation by 3, it becomes

3y/3 = (12-9x)/3

y= -3x + 4

using function notation,

y = f(x) = -3x + 4

8 0
3 years ago
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