Answer:
The symbiotic relationship between an anemone (Heteractis magnifica) and a clownfish (Amphiron ocellaris) is a classic example of two organisms benefiting the other; the anemone provides the clownfish with protection and shelter, while the clownfish provides the anemone nutrients in the form of waste while also scaring
Explanation:
I asked the same question
It gains a negative charge and becomes the ion <span>Cl-</span>
Answer:
Detail is given below.
Explanation:
Given data:
Mass of enzyme = 32 g
Volume of water = 42.50 mL
Volume of water+ enzyme = 48.0 mL
Density of enzyme = ?
Solution:
Density is equal to the mass divided by volume.
First of all we will calculate the volume of enzyme.
Volume of enzyme = (volume of water+ enzyme ) - Volume of water
Volume of enzyme = 48.0 mL - 42.50 mL
Volume of enzyme = 5.5 mL
Density of enzyme:
d = 32 g/ 5.5 mL
d = 5.8 g/mL
2)
Given data:
Mass of cup = 14 g
Volume of cup = ?
Density of cup = 2 g/cm³
Solution:
Density is equal to the mass divided by volume.
Formula:
d = m/v
2 g/cm³ = 14 g/ v
v = 14 g/2 g/cm³
v = 7 cm³
3) What are the four ways to measure matter?
weight, mass, volume, density
4) Given data:
Mass of rock = 18.5 g
volume of rock = 3cm³
density of rock = ?
Solution:
Formula:
d = m/v
d = 18.5 g/ 3cm³
v = 6.16 g/cm³
5)
Given data:
mass = 6g
density = 8 g/cm³
missing value = ?
Solution:
d = m/v
8 g/cm³ = 6g / v
v = 6g/8 g/cm³
v = 0.75cm³
6)
Given data:
Volume of liquid in cylinder = 48 mL
Volume of toy car and liquid = 52 mL
Volume of car = ?
Solution:
Volume of car = volume of of toy car and liquid - Volume of liquid in cylinder
Now we will put the values.
Volume of car = 52 mL - 48 mL
Volume of car = 4 mL
On the line above the tree line
