This question is a thought experiment.
It's essentially asking "Is 2πr² the same or not the same as π(2r)²?"
To figure it out, simply simplify π(2r)²
=π(2r)²
=π(2r)(2r)
=4πr²
Quite obviously, 2πr² is not the same as 4πr²
<span>Residual value is the difference between the observed value of the dependent variable (y) and the predicted value (ŷ) in a data set.
i.e. Residual value = given value - predicted value
From the table, the residual value corresponding to a has 4.1 as the given value and 4.5 as the predicted value.
Therefore, a = 4.1 - 4.5 = -0.4
Similarly, </span><span>the residual value corresponding to b has 7.2 as the given value and 7.05 as the predicted value.
Therefore, b = 7.2 - 7.05 = 0.15
</span>
Therefore, a = -0.4 and b = 0.15
The value of f(-1) is -11 if the function f(n) = 8n - 3 after plugging the value of n is -1
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
It is given that:
f(n) = 8n - 3
g(n) = 3n - 10
To find the value of f(-1) first plug n = -1 in the function f(n)
f(-1) = 8(-1) - 3
f(-1) = -8 - 3
f(-1) = -11
Thus, the value of f(-1) is -11 if the function f(n) = 8n - 3 after plugging the value of n is -1
Learn more about the function here:
brainly.com/question/5245372
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9.
2(13-p)
2(13-2)=22
2(13-3)= 20
2(13-4)= 18
10.
3v+w
3*4+2=14
3*6+3= 21
3*8+4= 28
11. you cannot see enough to do the problem so what ever the problem is you take the numbers and replace x with them 2 for the first one= x then do the problem to get the answer.
