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Rzqust [24]
4 years ago
6

Can someone please help me? I’m struggling . I’ll mark the correct answer most Brainly

Mathematics
1 answer:
mars1129 [50]4 years ago
8 0
You would add all of them together. Then since there is 4 round and green, you would do 4/23. The answer is .174
Hope this helped
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3 years ago
What is the volume of the following triangular prism?
sergiy2304 [10]

Answer:

<h2>288 ft³</h2>

Step-by-step explanation:

The formula of a volume of a prism:

V=BH

where

<em>B</em><em> - area of a base</em>

<em>H</em><em> - height of a prism</em>

<em />

In the base we have the right treiangle. The formula of an area of a right triangle is:

A=\dfrac{ab}{2}

where

<em>a, b</em><em> - are legs</em>

We have

a=6\ ft,\ b=8\ ft

Substitute:

B=\dfrac{(6)(8)}{2}=\dfrac{48}{2}=24\ ft^2

Calculate the volume.

Substitute

B=24\ ft^2,\ H=12\ ft

V=(24)(12)=288\ ft^3

3 0
3 years ago
Cdunwvwrnovnwvovnkvnoevnevne<br><br><br> help
Marysya12 [62]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Could someone answer this and explain an easier way to do this?
goblinko [34]

Answer:

Area of the figure = 109 cm. square

Step-by-step explanation:

The radius of the semi circle is 12 ÷ 2 = 6 cm.

Area of the semi circle = \frac{1}{2}\pi(6^{2})=18\pi

The radius of the quarter circle is 6 cm.

Area of the quarter circle = \frac{1}{4}\pi(6^{2}=9\pi

The area of the rectangle = 12 × 2 = 24

The area of the figure = 18π + 9π + 24 = 108.78 ≅ 109 cm. square

3 0
3 years ago
. You are interested in the amount of time teenagers spend weekly working at part-time jobs. A random sample of 15 teenagers was
agasfer [191]

Answer:

t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115    

Now we can calculate the degrees of freedom

df=n-1=15-1=14  

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got t_{critc}= 1.761

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

Step-by-step explanation:

Information given

\bar X=147.3 represent the sample mean for the amount of time spent at part time jobs

s=50 represent the sample standard deviation

n=15 sample size  

\mu_o =120 represent the value to check

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to analyze if the true mean for the amount of time spent at part time jobs is higher than 120, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115    

Now we can calculate the degrees of freedom

df=n-1=15-1=14  

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got t_{critc}= 1.761

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

4 0
3 years ago
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