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3 years ago

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The temp is 45 degrees F the temp will decrease by 2 degrees F each hour. Let h be the number be the number of hours. When will

the temp be below 35 degrees F? Write an inequality for this problem

1 answer:

Maurinko [17]3 years ago

6 0

45 - 2 x h < 35

It says "incorrect answer"?? I think that's the right answer, though.

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3 years ago

a fireplace contains 46 bricks along its bottom row. if each row above decreases by 4 bricks, what is the function that shows th

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$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
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d=\textit{common difference}\\
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a_1=46\\
d=-4\\
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\end{cases}
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3 years ago

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3 years ago

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In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta

Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.3246

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

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3 years ago

Find the nth term of this sequence, 3, 6, 9, 12

miss Akunina [59]

Answer:

$\large\boxed{\sf n^{th} \ term =3n}}$

Step-by-step explanation:

Find common difference from subtracting any term in the sequence with the previous term.

$\large{\sf 6-3}=3$

Apply nth term formula.

$\large{\sf a_n=a_1+(n-1)d$

$\large{\sf d=3 \ \ a_1=3}$

$\large{\sf a_n=3+(n-1)3$

$\large{\sf a_n=3+3n-3$

$\large{\sf a_n=3n}$

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