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leva [86]
3 years ago
8

Evaluate the expression 9(a+2b)+c for a=-3,b=-2, and c=1

Mathematics
1 answer:
dybincka [34]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
3 years ago
Help me please!!!! I don’t get this
Jet001 [13]
BCD should have to equal 24 degrees because angles ACB and BCD look Complimentary and a complimentary is 2 angles that equal 90 degrees when combined since ACB and BCD look like a 90 degree angle I would say that BCD is 24 degrees
7 0
3 years ago
Find the area of the irregular figure (use 3.14 for pi). Show your work. Round to the nearest tenth.
STatiana [176]
..............check above..........

7 0
3 years ago
Read 2 more answers
2 3/8 - 4 1/2 + 3 1/8 - (1/2)
UkoKoshka [18]

let's convert the mixed fractions to improper fractions firstly.

\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{19}{8}-\cfrac{9}{2}+\cfrac{25}{8}-\cfrac{1}{2}\implies \stackrel{\textit{using an LCD of 8}}{\cfrac{(1)19-(4)9+(1)25-(4)1}{8}}\implies \cfrac{19-36+25-4}{8} \\\\\\ \cfrac{4}{8}\implies \cfrac{1}{2}

8 0
3 years ago
There are two numbers, and one is 7 more than twice the other. The sum of the numbers is 43. What are the numbers? If x is less
chubhunter [2.5K]

Answer:

43-7=x

Step-by-step explanation:

5 0
2 years ago
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