Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Answer:
what is this and give more info next time too
Step-by-step explanation:
5/6= c/9
Cross mutiple. 5* 9= 45 . c*6
45= 6c
divide by 6 for 45 and 6c
45/6= 6c/6
45/6= c
Reduce 45/6. Divide by 3
45/3, 6/3
15/2= c
Answer: c= 15/2 or in decimal form , c= 7.5
Answer: it's not D i thought it was and I got it WRONG!!!
