<h2><u>Answer:</u></h2>
x=(nπ/2)±15
x=(2nπ+90)/3
x=90-2nπ
<h2><u>Steps:</u></h2>
cos3x+sin2x-sin6x+cos5x=0
(cos3x+cos5x)+(sin2x-sin6x)=0
equation(1)
<u>Use formula:</u>


<u>So in equation (1),if c=3x ,d=5x,C=2x,D=6x</u>
》2cos{(c+d)/2}.cos{(c-d)/2}+2cos{(C+D)/2}.sin{(C-D)/2}=0
》2cos{(3x+5x)/2}.cos{(3x-5x)/2}+2cos{(2x+6x)/2}.sin{(2x-6x)/2}=0
》2cos(4x).cos(-x)+2cos(4x).sin(-2x)=0
》2cos(4x)[cos(-x)+sin(-2x)]=0
》2cos(4x)[cos(x)-sin(2x)]=0
<u>1)</u><u> </u><u>Either:</u>
2cos(4x)=0
cos(4x)=0/2
cos(4x)=0
cos(4x)=cos(90)
General solution for such case is:X=2n±a
So,
4x=2nπ±90
x=(2nπ±90)/4
x=(nπ/2)±15
<u>2) Or:</u>
cos(x)-sin(2x)=0
cos(x)=sin(2x)
General solution for such case is:X=2n±a
So,
x=2nπ±(90-2x)
x=2nπ±90±2x
x±2x=2nπ±90
<u>Take +ve sign,</u>
x+2x=2nπ+90
3x=2nπ+90
x=(2nπ+90)/3
<u>Take -ve sign,</u>
x-2x=2nπ-90
-x=2nπ-90
x=(2nπ-90)/(-1)
x=90-2nπ
Answer:
2
Step-by-step explanation:
As you can see from the graph, the limit of f(x) when x tends to 3 from the right is 2.
By looking at the graph, you'll notice that for values greater than 3 f(x)=2.
Answer:
129
Step-by-step explanation:
the sum of the interior angles of a quadrilateral is 360, so you add 71+112+48 and subtract it from 360 to get x
Rational numbers can be defined as numbers that can be written in fractional notation. Let's consider an arbitrary number

, where a and b do not have common factors. This is an example of a rational number, as it can be described using a fraction. Real numbers and fractional numbers are among this branch of numbers.
Irrational numbers, on the other hand, are simply those numbers which cannot be written as an exact fraction, only approximated fractions. Famous cases of irrational numbers are those of π (pi), e (Euler's number/ Napier's constant), and many square root numbers.