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rjkz [21]
3 years ago
8

Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

, 5)
Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at (x_1,y_1) and point Q at (x_2,y_2) in the proportion a:b, we use the formula:

x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1

line segment PQ  is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1

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Answer:

Should be 4.0(Not sure tho. my thought process is complicated but to me it makes sense)

Step-by-step explanation:

If y=10 and x =2.5, if y were to = 20, then x would equal 5. so you take that ratio, and say 6 is 3/5's the way to 10, so you also divide 2.5 by 3/5

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3 years ago
Can someone explain thoroughly how I am meant to solve this?
BartSMP [9]

Answer:

I got x<equal to -11 or x>equal to4

Step-by-step explanation:

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7 0
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