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rjkz [21]
4 years ago
8

Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

, 5)
Mathematics
1 answer:
Yuri [45]4 years ago
4 0

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at (x_1,y_1) and point Q at (x_2,y_2) in the proportion a:b, we use the formula:

x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1

line segment PQ  is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1

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Lerok [7]

1. x^{2} -10x +25 = 0

These two numbers are: -5 and -5

-5 + (-5) = -10

-5 * -5 = 25

so...

(x - 5)(x - 5)

To find the roots set the factored numbers equal to zero and solve for x:

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2. x^{2} + 9x = -14

This equation needs to be equal to zero, so bring -14 to the other side by adding 14 to both sides

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Find two numbers that the sum is equal to 9 AND the multiplication of the numbers is 14

These numbers are 7 and 2

7 + 2 = 9

7*2 = 14

so...

(x + 2) (x + 7)

To find the roots set the each of the factored numbers equal to zero and solve for x:

x + 2 = 0

x = -2

x + 7 = 0

x = -7

3. 3x^{2} = 6x

This equation needs to be equal to zero, so bring 6x to the other side by subtracting 6x to both sides

3x^{2} -6x = 0

In this equation you can factor out a 3 and an x:

3x (x - 2)

To find the roots set the each of the factored numbers equal to zero and solve for x:

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Hope this helped!

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4 years ago
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