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Solnce55 [7]
3 years ago
5

△ABC has a>b>c. If one of the angles in the triangle is 60°, name the angle that can be equal to 90°.

Mathematics
2 answers:
defon3 years ago
8 0

Answer:

∠A = 90°

Step-by-step explanation:

In this question relation between angles a, b and c have been given.

If one angle is 60° then we have to find the angle which measure 90°.

In triangle ABC,

∠A + ∠B + ∠C = 180°

If angle B = 60°

Then ∠A + 60 + ∠C = 180

∠A + ∠C = 180 - 60

∠A + ∠C = 120°

We know ∠A > ∠C

Therefore, ∠A = 90°

and ∠C = 30°

Now the angles of the triangle will be

∠A = 90°

∠B = 60°

∠C = 30°

∠A = 90° will be the answer.

Aleksandr-060686 [28]3 years ago
4 0

Answer:

Angle A

Step-by-step explanation:

a is greater than b, which is greater than c

a triangle has 180 degrees

so 180-90 is 90

90-60 is 30

a>b>c

90>60>30

this would be a right triangle since one of the angles is 90 degrees

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Answer: $70 per year.

Step-by-step explanation:

Let's say that x is the number of years that has passed and y is how much the stamp is worth.

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Now we know that in 8 years it was worth $980 and that could be the coordinates (8,980)

To find the rate of change we need to find the different between the y value and divide it by the difference in the x values.

420 - 980 = -560

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galina1969 [7]

Answer:

The key is to prove that the triangles are congruent, then their corresponding parts are congruent.

Step-by-step explanation:

#5)

It it given that:

Angle CBD is congruent to angle CDB.

Angle BAE is congruent to angle DEA.

Triangle CBD is isosceles because it's base angles are equal. Therefore, segment CB is congruent to segment CD.

Triangle CAE is isosceles because it's base angles are equal. Therefore, segment CA is congruent to segment CE.

CA-CB=BA

CE-CD=DE

segment BD is congruent to segment DB.

Angle ABD is supplementary to angle CBD (180-angle CBD= angle ABD).

Angle EDB is supplementary to angle CDB (1980-angle CDB=angle EDB).

therefore, angle ABD=angle EDB.

Triangles ABD and EDB are congruent because of the Side-angle-side theorem.

Triangles ABD and EDB are congruent, segment AD is congruent to segment EB because corresponding legs of congruent triangles are congruent.

#6)

It is given that:

Angle EBC is congruent to angle ECB

Segment AE is congruent to segment DE.

Triangle BEC is iscsceles because it's base angles are equal. Therefore, segment EB is congruent to segment EC.

AE+EC=AC

DE+EB=DB

segment BC is congruent to segment CB.

Triangle BAC is congruent to triangle CDB because of the side-angle-side theorem.

Segment AD is congruent to segment DC because corresponding legs of congruent triangles are congruent.

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3 years ago
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