Plz help me (All my points if correct)
1 answer:
Answer:
12 bats
Step-by-step explanation:
Let us number the bat caves from 1 to 45 and divide them into 5 parts:
a) 1
b) 2 to 29 ( bats)
c) 30
d) 31 to 44 ( bats)
e) 45
It is given that any 7 caves in a row has 77 bats. Hence, the total number of bats in part b and d = ( ) + (
) = 462 bats.
There remains ( 490 - 462 ) = 28 bats in cave number 1, 30 and 45.
Now, our question demands the maximum possible number of bats in cave 30.
Minimum number of bats in a cave is 2. So we shall put 2 bats in the last cave, which gives us bats in the first cave.
Therefore, the greatest possible number of bats in cave number 30 = ( 28 - 2 - 14 ) = 12 bats.
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