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3 years ago

Form a sequence that has two arithmetic means between -13 and 89.

Mathematics

2 answers:

scoray [572]3 years ago

8 0

It would be D. If you add all the numbers (-18, -81, 144) and divide it by 3 then you would get -81. I hope I helped!

goldenfox [79]3 years ago

4 0

Compare the problem statement to the answer choices. (Check the offered answers.) Only the first two sequences start with -13 and end with 89, so selections (b) and (d) can be rejected. The differences between terms of sequence (a) are not constant, so it is not an arithmetic seqence. That only leaves ...
c. -13, 21, 55, 89

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Zia is building a plastic model rocket that has the combined shape of a cone and a cylinder as shown. additionally, the cylinder

scoray [572]

Answer:

226 cm^3

The mass of plastic used to make cylinder is greater

Step-by-step explanation:

Given:-

- The density of cone material, ρc = 1.4 g / cm^3

- The density of cylinder material, ρl = 0.8 g / cm^3

Solution:-

- To determine the volume of plastic that remains in the cylinder after gouging out a hemispherical amount of material.

- We will first consider a solid cylinder with length ( L = 10 cm ) and diameter ( d = 6 cm ). The volume of a cylinder is expressed as follows:

$V_L =\pi \frac{d^2}{4} * L$

- Determine the volume of complete cylindrical body as follows:

$V_L = \pi \frac{(6)^2}{4} * 10\\\\V_L = 90\pi cm^3\\$

- Where the volume of hemisphere with diameter ( d = 6 cm ) is given by:

$V_h = \frac{\pi }{12}*d^3$

- Determine the volume of hemisphere gouged out as follows:

$V_h = \frac{\pi }{12}*6^3\\\\V_h = 18\pi cm^3$

- Apply the principle of super-position and subtract the volume of hemisphere from the cylinder as follows to the nearest ( cm^3 ):

$V = V_L - V_h\\\\V = 90\pi - 18\pi \\\\V = 226 cm^3$

Answer: The amount of volume that remains in the cylinder is 226 cm^3

- The volume of cone with base diameter ( d = 6 cm ) and height ( h = 5 cm ) is expressed as follows:

$V_c = \frac{\pi }{12} *d^2 * h$

- Determine the volume of cone:

$V_c = \frac{\pi }{12} *6^2 * 5\\\\V_c = 15\pi cm^3$

- The mass of plastic for the cylinder and the cone can be evaluated using their respective densities and volumes as follows:

$m_i = p_i * V_i$

- The mass of plastic used to make the cylinder ( after removing hemispherical amount ) is:

$m_L = p_L * V\\\\m_L = 0.8 * 226\\\\m_L = 180.8 g$

- Similarly the mass of plastic used to make the cone would be:

$m_c = p_c * V_c\\\\m_c = 1.4 * 15\pi \\\\m_c = 65.973 g$

Answer: The total weight of the cylinder ( m_l = 180.8 g ) is greater than the total weight of the cone ( m_c = 66 g ).

8 0

3 years ago

Find the area cut out of the cylinder x^2 + z^2 = 36 by the cylinder x^2 + y^2 = 36.

Zanzabum

This is the concept of algebra, we are required to calculate the area cut out of a cylinder represented by the function x^2+z^2=36;
The equation of a circle is given by:
(x-a)^2+(y-b)^2=r^2
where;
(a,b) are the center of the circle;
r=radius of the circle
re-writing our equation we have:
x^2+z^2=36
(x-0)^2+(z-0)^2=6^2
this implies that the center of the circle is (0,0) and the radius is 6 units;
Therefore the area will be given by:
Area=πr^2
Area=π*6^2
Area=36π=113.1 sq. units

7 0

3 years ago

The booster club raised $102 in there car wash. They want to buy $18 soccer balls for the soccer team. Write and solve an inequa

sergey [27]

Answer:

X=5

Step-by-step explanation:

$102=18x$ , then divide both sides by 18 which gives you 5.666667 but you cant buy half a ball they can only afford 5 balls with $12 left over.

3 0

3 years ago

Please help me i dont understand

Phantasy [73]

Answer:

E and A

Step-by-step explanation:

3 0

3 years ago

11x squared times 3x

belka [17]

Answer:

363 should be your answer

Step-by-step explanation:

8 0

3 years ago