Question

Farmer Jones raises ducks and cows. He looks out his window and sees 54 animals with a total of 122 feet. If each animal is “normal”, have many of each type of animal does he have

Answer 1

Answer:

He have 47 ducks and 7 cows.

Step-by-step explanation:

Given:

Farmer Jones raises ducks and cows.

He looks out his window and sees 54 animals with a total of 122 feet.

Now, to find the each type of animal he have.

Let the number of ducks be $x.$

And the number of cows be $y.$

So, total number of animals are:

$x+y=54$

$x=54-y$  ....( 1 )

As, the feet of cows are 4 and ducks are 2.

Now, the total number of feet are:

$2(x)+4(y)=122$

$2x+4y=122$

Substituting the value of $x$ from equation (1) we get:

$2(54-y)+4y=122$

$108-2y+4y=122$

$108+2y=122$

Subtracting both sides by 108 we get:

$2y=14$

Dividing both sides by 2 we get:

$y=7.$

The number of cows = 7.

Now, to get the number of ducks we substitute the value of $y$ in equation (1):

$x=54-y\\x=54-7\\x=47.$

The number of ducks = 47.

Therefore, he have 47 ducks and 7 cows.