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4 years ago

P and Q are points on the line y= 2 -4x complete the coordinates of P and Q, P(0, ) Q( ,0)

Mathematics

1 answer:

docker41 [41]4 years ago

4 0

(d): y=2-4x
P(0;y) belongs to (d)
=> y=2-4*0
= 2
So P(0;2)
Q(x;0) belongs to (d)
=> 0=2-4*x
<=> x=1/2
So Q(1/2;0)

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Please help me complete this chart. No URLS

kipiarov [429]

Answer
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3 years ago

How many times smaller is 2 × 10^-10 than 4 × 10^-5

natta225 [31]

Answer:

200,000

Step-by-step explanation:

To find how many times smaller is smaller number than greater number, divide greater number by smaller number.

Greater number $=4\times 10^{-5}$

Smaller number $=2\times 10^{-10}$

Then

$\dfrac{\text{Greater number}}{\text{Smaller number}}\\ \\=\dfrac{4\times 10^{-5}}{2\times 10^{-10}}\\ \\=\dfrac{4}{2}\times \dfrac{10^{-5}}{10^{-10}}\\ \\=2\times \dfrac{1}{10^{-5}}\\ \\=2\times 10^5\\ \\=2\times 100,000\\ \\=200,000$

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4 years ago

Simplify <br><br> ( 8 x 10^2) ( 2 x 10^2)<br><br> I Need help!

DiKsa [7]

1.6(10^2) is what I got but I guess I don’t fully know

6 0

3 years ago

Circle P has a circumfrence of aproximately 75 inches what is the aproximate length of the radius, r? Use 3.14 for pi. Round to

ratelena [41]

Answer:

The approximate length of the radius, r is 12 inch.

Step-by-step explanation:

Given:

A circle P is given having circumference C,

C = 75 inch

pi = π = 3.14

radius = r

To Find:

radius = r = ?

Solution:

Circumference:

In geometry, the circumference (from Latin circumferens, meaning "carrying around") of a circle is the (linear) distance around it.

That is, the circumference would be the length of the circle if it were opened up and straightened out to a line segment.

Formula is given as

$Circumference=2\pi (radius)$

Substituting the values we get

75 = 2 × 3.14 × r

∴ $r =\frac{75}{2\times 3.14}\\ \\r=\frac{75}{6.28} \\\\r=11.942\ inches$

We approximate radius to

radius = 12 inich

7 0

3 years ago

What is a11. A12. A21. A22

Ierofanga [76]

Answer:

$a_{11} =-1\\a_{12} =3\\a_{21} =5\\a_{22} =3/2\\$

Step-by-step explanation:

$2X-\left[\begin{array}{ccc}-4&8\\2&-2\end{array}\right] =\left[\begin{array}{ccc}2&-2\\8&5\end{array}\right]\\X=\frac{1}{2} (\left[\begin{array}{ccc}-4&8\\2&-2\end{array}\right] +\left[\begin{array}{ccc}2&-2\\8&5\end{array}\right])\\X=\frac{1}{2} (\left[\begin{array}{ccc}-4+2&8-2\\2+8&-2+5\end{array}\right] )\\X=\frac{1}{2} (\left[\begin{array}{ccc}-2&6\\10&3\end{array}\right] )\\X= (\left[\begin{array}{ccc}\frac{1}{2}(-2)&\frac{1}{2}(6)\\\frac{1}{2}(10)&\frac{1}{2}(3)\end{array}\right] )\\$

$X= (\left[\begin{array}{ccc}-1&3\\5&3/2\end{array}\right] )$

$a_{11} =-1\\a_{12} =3\\a_{21} =5\\a_{22} =3/2\\$

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3 years ago