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In-s [12.5K]
4 years ago
11

P and Q are points on the line y= 2 -4x complete the coordinates of P and Q, P(0, ) Q( ,0)

Mathematics
1 answer:
docker41 [41]4 years ago
4 0
(d): y=2-4x
P(0;y) belongs to (d)
=> y=2-4*0
= 2
So P(0;2)
Q(x;0) belongs to (d)
=> 0=2-4*x
<=> x=1/2
So Q(1/2;0)
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Line GJ is tangent to point A at point G.<br><br> If AG = 9 and GJ = 12, find AJ.
kompoz [17]
GJ is a tangent
АG is a radius
A tangent line to a circle is perpendicular to the radius drawn to the tangent point   ⇒ m∠АGJ = 90°  ⇒ ΔАGJ is the right triangle.

<span>By the Pythagorean theorem:
</span>AJ² = АG² + GJ²
AJ² = 9² + 12² = 81 + 144 = 225
AJ = √225 = 15 units.
4 0
3 years ago
Read 2 more answers
Factor <br><br> LaTeX: 7v^2+31v+12
bazaltina [42]

Answer:

(7v +3 ) ( v    + 4  )

Step-by-step explanation:

7v^2+31v+12

(7v + ) ( v    +   )

12 = 1*12

       2*6

       3*4

7* 4 + 3 = 31

(7v +3 ) ( v    + 4  )

6 0
3 years ago
Please help me. The question is in the image.
Varvara68 [4.7K]

Answer:

10=x

Step-by-step explanation:

Intersecting Chords Formula:(segment piece) x (segment piece) =

       (segment piece) x (segment piece)

6*5 = 3*x

30 = 3x

Divide by 3

30/3 = 3x/3

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8 0
3 years ago
One number exceeds another by 1. the sum of the numbers is 21. what are the numbers
Cerrena [4.2K]
Try this solution:
1. if 1st number is 'x', the 2d number is 'y', then it is possible to make up the system of two equation according to the condition:
\left \{ {{x-y=1} \atop {x+y=21}} \right. \ =\ \textgreater \  \  \left \{ {{x=11} \atop {y=10}} \right.
2. one number is 11, another number is 10.
3 0
3 years ago
Eight times a number plus five another number is -13. The sum of the two numbers is 1. What are the numbers?
Pani-rosa [81]
Eight *(a number) plus 5*(another number) is -13.

translates to:

8(x) + 5(y) = -13

The sum of (the number) and (the other number) is 1.

translates to:

(x) + (y) = 1


We have a system of two equations involving two unknowns: x and y.

\rm 8x+5y=-13\\&#10;~~x+~~y=~~~~1

We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.

We'll multiply the second equation by -8 so that the x's match up.

\rm ~~~8x+5y=-13\\ -8x-8y=-8

When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.

\rm -3y=-21

Divide by -3,

\rm y=7

Plug back into one of your original equations to find the value of x,

\rm x+y=1\\&#10;x+7=1

Subtract 7,

\rm x=-6
8 0
3 years ago
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