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Natali5045456 [20]
3 years ago
13

A member only speaker series allows people to join for 6$ and then pay 4$ for every event attended .What is the maximum number o

f events someone can attend for a total cost of 50$
Mathematics
1 answer:
nlexa [21]3 years ago
3 0

Answer:

11

Step-by-step explanation:

50-6=44

44/4=11

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How do the expressions 8+k2−6 and 8(k+2)−4k compare when k = 7?
Andreas93 [3]

Answer:

8+k2-6>8(k+2)-4k

Step-by-step explanation:

8+7×2-6 and 8(7+2)-4×7

8+14-16 and (56+16)-28

6 and 44

8 0
3 years ago
From a club of 24 people, in how many ways can a group of four members be selected to attend a conference?
Kamila [148]

Answer:

255,024

Step-by-step explanation:

24 x 23 x 22 x 21

24 options for the first member

23 options for the second member

22 options for the third member

21 options for the last member

6 0
3 years ago
The poster shows how many of its games of football team has won so far.Express this information as a fraction a,percent and as a
Harrizon [31]
12/15
Divide 12 by 15 and then you should get 0.8
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4 0
3 years ago
How can I solve 2x+y=-3
Vladimir79 [104]

Answer:

If solving for x then x = -3/2 +y/2

If solving for y then y = -3-2x

Step-by-step explanation:

For x: Divide both sides by 2

For y: Subtract 2x from both sides of the equation

4 0
3 years ago
How would you prove this trigonomic identity? Please show steps.
Agata [3.3K]

Start by combining the fractions:

\dfrac{\cos\alpha}{1+\sin\alpha}\cdot\dfrac{1-\sin\alpha}{1-\sin\alpha}+\dfrac{\cos\alpha}{1-\sin\alpha}\cdot\dfrac{1+\sin\alpha}{1+\sin\alpha}

\dfrac{\cos\alpha(1-\sin\alpha)+\cos\alpha(1+\sin\alpha)}{(1+\sin\alpha)(1-\sin\alpha)}

\dfrac{2\cos\alpha}{1-\sin^2\alpha}

Recall the Pythagorean identity:

\dfrac{2\cos\alpha}{\cos^2\alpha}

Then cancel a factor of \cos\alpha and use the definition of secant:

\dfrac2{\cos\alpha}=\boxed{2\sec\alpha}

4 0
3 years ago
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