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Marizza181 [45]
3 years ago
14

I need help please ?!!

Mathematics
2 answers:
densk [106]3 years ago
7 0
The answer to that might be 9. If it is referring to how many digits are in between 0 and -9.
dsp733 years ago
4 0
Count from -9 to 0 on a number line and you’ll get 9.
You might be interested in
Solve for (a+1)/2=1/a.
LenKa [72]

Hello!

To solve this, you are trying to convert one side to a quadratic equation and the other to just 0. Then, solve the equation.

----

First, move the /2 to the other side of the equation.

(a+1)/2 = 1/a

a+1 = 2/a

Next, multiply both sides by a.

a+1 = 2/a

a^{2} +a=2

And then subtract both sides by 2. This will get you to a quadratic equation.

a^{2} +a=2

a^{2} +a-2=0

Now, factor the equation. When we're factoring, we are looking for the form (a + b)(a + c), where b + c must equal 1 (the coefficient of a) and b*c must equal -2. In this case, b = 2, and c = -1.

Therefore:

a^{2} +a-2=0

(a + 2)(a - 1) = 0

To get the answer, recall that anything multiplied by 0 is equal to 0. Therefore, to get the left side to equal 0, either (a + 2) or (a - 1) must equal 0. To do this, a must either be -2 or 1.

Therefore, a = -2, or a = 1.

----

Check your work:

(-2 + 1)/2 = 1/-2

-1/2 = -1/2

(1 + 1)/2 = 1/1

2/2 = 1/1

1 = 1

----

Hope this helps!

6 0
3 years ago
Need help fast please
dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is  -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4


14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0


15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x


16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

y=3x-10


 

8 0
4 years ago
Given that f(x) = x^2? + 9x + 18 and g(x) = x + 3, find (f ÷ g) (x) and express the result in standard form.​
lawyer [7]

Answer:

x + 6

Step-by-step explanation:

(f ÷ g)(x)

= \frac{x^2+9x+18}{x+3} factorise the numerator

= \frac{(x+3)(x+6)}{x+3} ← cancel the factor (x + 3) on numerator/ denominator

= x + 6

5 0
3 years ago
How many unique triangles can be made if one is 90'and the other is half
gtnhenbr [62]
Only one because the angles must add up to 180 degrees 
8 0
4 years ago
How to write 5 and 8 in a inequality​
Reil [10]
The answer would be 5<8 because 8 is greater than 5.
7 0
3 years ago
Read 2 more answers
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