Question

Given a number N, write a code to print all psoitive numbers less than N in which all adjacent digits differ by 1

Answer 1

Answer:

def lesser_adjacent_num ( N ):

     N = int( N )

     while N == True:

            next = N - 1

            print if  next >= 0 ? next : break

Explanation:

The python function above called "lesser_adjacent_num" accepts an argument called "N" which is an integer. The function print the number "next" which is a number less than the N integer for every loop for the condition where N is not zero.