Hey there!
To solve the first problem, I've found it easiest to solve the equation for, say, values –2 through +2 and create a table of values for you to begin graphing this function. You may need to do more depending on the equation itself.
Some points are: (–2, 0.75), (–1, 1.5), (0, 3), (1, 6) and (2, 12). You can check which graph matches up with these points the closest to get your answer of D.
To solve the second problem, you'll need to use the distance equation.
x1 = –4, y1 = 3
x2 = –1, y2 = 1
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√ (x2–x1)^2 + (y2–y1)^2
_________________
√ (–1–(–4)^2 + (1–3)^2
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√ (–1+4)^2 + (–2)^2
____________
√ (3)^2 + (–2)^2
_____
√ 9 + 4
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√ 13, making your answer D
For your third question, I always just counted the number of units the point was from the line of reflection. You'll count twice diagonally towards the line from point C for this one, staying on the "crosshairs" of the graph. All you need to do then is count two diagonal units along the same line, then you'll get your answer of (2, 6), or D.
For your final question, A and B are immediately out, since they won't be parallel to the 4x equation. You'll need to solve both of your remaining equations for y with 2 plugged in for x; whichever one equals 7 will be your answer. In this case, it will be D.
Hope this helped you out! :-)
Answer:
a
Step-by-step explanation:
Answer:
13:8
is the answer because if you take the games won and lost this is what you get
Step-by-step explanation:
No need to fear, thehotdogman93 is here!
The first step is to get rid of those very large numbers. It's going to be very difficult to factor unless we can bring those high numbers down. So lets see if we can factor each term.
So after dividing 49 with every single digit. The only number that divides evenly is 7 and one, and 16 isnt divisible evenly by 7 so that didn't work. Looks like we're gonna have to work with these big numbers.
There is something interesting though about these numbers. 16 and 49 are both perfect squares. 16 is the same as 4^2 and 49 is the same as 7^2. So we can factor the whole trinomial as:
If we were to expand this out as:
and multiply it back into the original form. It would match with the expression we started with. The 4's would multiply back into 16x^2 and the 7's would multiply back into 49.
Additionally 4 * -7 is -28, so you can combine two -28x's into the -56x term in the original trinomial.
Thus, the answer is yes you can, and the answer is:
Answer:
Step-by-step explanation:
P(x) = x² - 1 and Q(x) = 5(x - 1)
(P - Q)(x) = x² - 1 - 5(x - 1)
= x² - 1 - 5x + 5
= x² - 5x + 4
