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faltersainse [42]
3 years ago
11

A cube has six congruent faces that are all

Mathematics
1 answer:
erica [24]3 years ago
5 0
Well you could just say that they have 6 congruent faces that have all the same measurements, as well as the same surface area. 
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What is the area of this triangle 12 m 13 m and 5 m is the measurements of the triangle
VashaNatasha [74]

Answer:

30 m^2.

Step-by-step explanation:

This  is a right-angled triangle because it obeys the Pythagoras theorem

( 13^2 = 12^2 + 5^2).

So its area = 1/2 * base * height

= 1/2 * 5 * 12

= 30 m^2

7 0
3 years ago
Find the area of the composite figure​
ehidna [41]
<h3>62.5 cm^2</h3>

The figure is a trapezoid, albeit not possessing the same lengths for the left and right sides. If I'm not mistaken, it has another name or term. But I forgot.

Anyway, to solve the problem, let us chop-chop or break the figure into two parts or two polygons that we are familiar with - a rectangle and a triangle. See the attached image for a clearer presentation.

After breaking the original polygon into two parts as portrayed by the red broken line, we are also going to divide the equivalent value of each side.

Remember, a rectangle has two pairs of common sides. Since the upper side of the polygon has a length of 10 cm, then, the length of the lower side (the side at the left side of the broken line) is 10, too. The same goes for the length of the left side which is 5 cm, and therefore the length of the broken line is 5 cm. Please refer to the attached image, particularly the figures in green.

From the standpoint of the triangle, based on thee figure, it has a height of 5 cm and a base of 5 cm (15 cm- 10 cm). Did you get it? If yes, let's continue.

Solving Time! :D

1. Solve for the area of the rectangle.

\begin{gathered}A_{rectangle}=L\times W\\=5\ cm \times 10\ cm\\=\bold{50\ cm^2}\end{gathered}

Arectangle=L×W=5 cm×10 cm=50 cm²

2. Solve for the area of the triangle.

\begin{gathered}A_{triangle}=\dfrac{b\times h}{2}\\=\dfrac{5\ cm\times5\ cm}{2}\\=\dfrac{25\ cm^2}{2}\\=\bold{12.5\ cm^2}\end{gathered}

Atriangle=2b×h=25 cm×5 cm=225 cm²=12.5 cm²

3. Combine (add) the two areas to find the area of the original figure.

\begin{gathered}A_{composite\ figure}=A_{rectangle}+A_{triangle}\\=50\ cm^2 +12.5\ cm^2\\=\bold{62.5\ cm^2}\end{gathered}

Acomposite figure=Arectangle+Atriangle=50 cm²+12.5 cm2=62.5 cm

If there's a Latex Error, Please click the second image attached below :)

4 0
2 years ago
Molly needs to classify the triangle below based on angles. Which class is correct? 60° 50° 70° A. acute triangle О B. isosceles
Art [367]

Answer:

A. Actute triangle

Step-by-step explanation:

Is A because an acute triangle is a triangle where all the angles are the same.

Can not be B. because isosceles triangles have two sides that are the same which doesn't relate to angles.

Can not be C. because equilatiral triangles are triangles with sides that are all the same.

Can not be D. because for a triangle to be obtuse one of the angles needs to be greater that 90 degrees.

So it has to be A.

7 0
2 years ago
Simplify the expression below
Degger [83]

Answer:

jjjh;kn jhuj hnpjinp; inj in

Step-by-step explanation:

6 0
2 years ago
PLS help. 30 points and brainliest
iren2701 [21]
What is angle A’s equation
8 0
3 years ago
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